10:20 Exam II Key; FALL 2009 Dr. Williamson
| Pink, Exam II, v1 | Blue, Exam II, v2 | QUESTION | Yellow, Exam II, v3 |
| 6 pts each unless noted | 6 pts each unless noted | 6 pts each unless noted | |
| C(D=3pts) | C (A=3pts) | 1 | D |
| B | A | 2 | E |
| C | D (C,E=3pts) | 3 | B |
| E (A,D=3pts) | B | 4 | A (E=3pts) |
| A | E | 5 | B |
| E (B=3pts) | C | 6 | A |
| C | A | 7 | C (B,E=3pts) |
| D (B=3pts) | C (E=3pts) | 8 | D |
| A | A | 9 | C |
| B | E (D=3pts) | 10 | A (B,E=3pts) |
| D (B,E=3pts) | B (D=3pts) | 11 | C (D=3pts) |
| A | B (A,E=3pts) | 12 | A (D=3pts) |
| A (C=3pts) | C | 13 | E (C=3pts) |
| B | E | 14 | D |
(14 x 6) = 84 pts on multiple choice
16 more points on short answer-See the bulletin board outside room 123b for the
solutions.
PINK EXAM
| #15 (8 pts) (a) 2Na3PO4(aq) + 3Mg(NO3)2 (aq) --> 6NaNO3(aq) + Mg3(PO4)2(s) net ionic = 2PO43- (aq) + 3Mg2+(aq) --> Mg3(PO4)2(s) (b) no reaction (c) HNO2(aq) + NaOH(aq) --> NaNO2(aq) + H2O(l) net ionic = HNO2(aq) + OH-(aq) --> NO2-(aq) + H2O(l) |
#16 (8pts) N2 + 3H2 -->
2NH3 limiting = N2 g of NH3 = 1.2 g (2 sig figs) % Y = 79% |
BLUE EXAM
| #15 (8 pts) (a) H2SO4(aq) + Mg(OH)2(s) --> MgSO4(aq) + 2H2O(l) net ionic = 2H+(aq) + Mg(OH)2(s) --> Mg2+(aq) + 2H2O(l) (b) 3Na2S(aq) + Fe2(SO4)3 (aq) --> 3Na2SO4(aq) + Fe2S3(s) net ionic = 2Fe3+ (aq) + 3S2-(aq) --> Fe2S3(s) (c) no reaction |
#16 (8pts) C2H4 +
3O2 --> 2CO2 + 2H2O limiting = O2 g of CO2 = 2.8 g (2 sig figs) % Y = 71% |
YELLOW EXAM
| #15 (8 pts) (a) 3Na2S(aq) + Fe2(SO4)3 (aq) --> 3Na2SO4(aq) + Fe2S3(s) net ionic = 2Fe3+ (aq) + 3S2-(aq) --> Fe2S3(s) (b) HNO2(aq) + KOH (aq) --> KNO2(aq) + H2O(l) net ionic = HNO2(aq) +OH-(aq) --> NO2-(aq) + H2O(l) (c) no reaction |
#16 (8pts) C + 2Cl2 -->
CCl4 limiting = Cl2 g of CCl4 = 168g (3 sig figs) % Y = 75.0% |